What is the magnetic moment (spin only) and h | vedclass

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Question

(C) In the brown ring complex $[Fe(H_2O)_5NO]SO_4$,the iron is in the $+1$ oxidation state $(Fe^+)$.The electronic configuration of $Fe^+$ is $[Ar] 3d

Vedclass · Accepted Answer

$\sqrt{15} \ BM, sp^3d^2$

Vedclass · Answer

(C) In the brown ring complex $[Fe(H_2O)_5NO]SO_4$,the iron is in the $+1$ oxidation state $(Fe^+)$.The electronic configuration of $Fe^+$ is $[Ar] 3d^6 4s^1$.In this complex,$NO$ acts as $NO^+$,and $H_2O$ is a weak field ligand. The $Fe^+$ ion undergoes $sp^3d^2$ hybridisation.The $3d$ electrons are arranged as $t_{2g}^5 e_g^0$ (or similar distribution),resulting in $3$ unpaired electrons.Magnetic moment $\mu = \sqrt{n(n+2)} \ BM = \sqrt{3(3+2)} = \sqrt{15} \ BM$.Thus,the magnetic moment is $\sqrt{15} \ BM$ and the hybridisation is $sp^3d^2$.

List-$I$ $(Compounds)$	List-$II$ $(Hybridization)$
$(a)$ $[Ni(NH_3)_6]^{+2}$	$(i)$ $sp^3 d^2$
$(b)$ $[PtCl_4]^{-2}$	$(ii)$ $dsp^2$
$(c)$ $[Ni(CO)_4]$	$(iii)$ $sp^3$
$(d)$ $[Co(OX)_3]^{-3}$	$(iv)$ $d^2 sp^3$

What is the magnetic moment (spin only) and hybridisation of the brown ring complex $[Fe(H_2O)_5NO]SO_4$?

Similar Questions

Identify the coordination complexes in which the central metal ion has $d^4$ configuration.
$(A)$ $[FeO_4]^{2-}$
$(B)$ $[Mn(CN)_6]^{3-}$
$(C)$ $[Fe(CN)_6]^{3-}$
$(D)$ $[Cr(H_2O)_6]^{2+}$
$(E)$ $[NiF_6]^{2-}$
Choose the correct answer from the options given below:

Which type of atomic orbitals hybridize to form a square planar complex?

Which of the following pairs of compounds is planar?

What is the coordination number of the central metal ion if it forms an octahedral complex?

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